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Pass chimed in before I posted, but I had to run so I didn't go back through my post. There’s also a link to the Duncan PSU Designer II that can be helpful to quickly see proposed variations. The Choke Input PSU is a whole different animal. Refer article on RF Filter Design and RF Filter calculator for more information. Following are the equations used in this Pi filter. 2 sqrt(2)/pi 0. Example : INPUTS : Fc 900 MHz, Z0 50 Ohm OUTPUTS: L 1.76 x 10-8 Henries, C 7.077 x 10-12 farads Pi low pass filter Formula. If the inductor had no DC resistance, the average voltage at its other end would be exactly the same. How much is enough? I think there’s a lot of leeway in the amount of inductance need to suppress the ripple noise. The rectified voltage is then ideally on average 2/pi times the peak voltage minus some drop across the diode, so ideally 2 sqrt(2)/pi times the RMS voltage minus some drop across the diode. The voltage drop across the choke will fluctuate causing the rail voltage to fluctuate with variations in current draw. For an Aleph2 you should, IMO, use at least 12 gauge windings, but the trick is to get enough inductance with as low a DC resistance as possible because its wasted watts. The wattage it will have to handle is determined by the DC resistance and the continuous current (I*I*R). L ( this is my second question) with regards. ,(this is my question) C obtained with the help of PI spread sheet. You want a choke that can handle the maximum current/rail (peak) and the continuous current/rail. Suppose if were to use this formula to calculate the value of the inductor what will be the cutoff frequency for this filter., F 1/ (2PI(SQRT(LC)) Here F whether it will be 50Hz. I try to ensure that the combination of the inductance, capacitance and internal resistance of the choke (+ any actual resistors) is it at least critically damped. The pi filter is a type of passive inductor-capacitor (LC) filter that features its components in a ‘pi’ shaped configuration. If you aren't looking for a choke-input supply, then you can pick pretty much any value you like. Current squared times its internal resistance can get you a first pass at the power handling needs. It would have to be able to cope with a constant 2A draw. So for a 32 volt ouput and a 2 amp current draw you would need an inductance of. L (given in henries) = (desired output voltage) / (current draw in milliamps) They didn't say how they derived it and I've been too lazy to figure it where it might have come from. The low-pass filter used for power supply filtering is formed from an inductor in series between the input and output with two capacitors, one across the input and the other across the output. The only rule of thumb I've seen for specifying the size of an inductor in a power supply came from the 1970 edition of the Radio Amateur's Handbook That formula was given to ensure that the inductance was sufficient to cause the filter to act as a proper choke-input supply. Pi filters can be designed as either low pass or high pass filters, depending on the components used. Designing a pi filter (C-L-C) for the output of a TPS62740 buck converter.